Natural Chemistry Filter
Analytical chemistry question?
A calcium in a 200.0 mL of a natural H2O was determine by precipitating the cation as CaC2O4. The precipitate was filtered, washed and ignited in a crucible with an empty mass of 26.6002 grams. The mass of crucible plus CaO was 26.7134 grams. Calculate the concentration of calcium in water in g/100mL
mass CaO = 26.7134 - 26.6002 = 0.7114 g
moles CaO = 0.7114 g / 56.077 g/mol=0.01239
= moles Ca in 200 mL
moles Ca in 100 mL = 0.01239/2=0.006195
[Ca2+]= 0.006195 mol/100 mL
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